Question

If the sum of the zeroes of the quadratic polynomial 3x2

-kx+6 is 3, then find

the value of k.

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Answer 1

Answer:

given one root of the Equation is 3

3x^2-kx+6=0

3(3)^2-k*3+6=0

3*9-3k+6=0

27-3k+6=0

-3k+33=0

-3k=-33

k=33/3

k=11

The value of k is 11

Answer 2

Answer:

9

Step-by-step explanation:

Hi ,

Compare 3x² - kx + 6

with ax² + bx + c,

a = 3 ,

b = - k ,

c = 6 ,

According to the problem given ,

Sum of the zeroes = 3 ---( 1 )

- b / a = 3

- ( - k ) / 3 = 3

k / 3 = 3

k = 9

I hope this helps you.