Question

If the sum of the zeroes of the quadratic polynomial 3x2

-kx+6 is 3, then find

the value of k.​

Answer 1

Explanation:

sum of zeros=3

polynomial -3^2-Kx+6

a=3 b= -k c= 6

so alpha+beeta = -b/a

3= -(-k)/3

k= 3×3

=9

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