Question

If the sum of the zeroes of the quadratic polynomial 3x2-kx+6 is 3, then find
the value of k.
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Answer 1

Answer:

$3(3) {}^{2} - k3 + 6 = 0 \\ 3 \times 9 - 3k + 6 = 0 \\ 27 + 6 - 3k = 0 \\ 33 - 3k = 0 \\ - 3k = - 33 \\ 3k = 33 \\ k = \frac{33}{3} \\ . = 11$

hope the solution helps