Question

If the sum of the zeroes of the quadratic polynomial 5x

2

-kx+6 is 4, then find the value of

k.​

Answer 1

$sum \: \: of \: \: zeroes = \\ \\ \frac{ - ( coefficient \: \: of \: \: x)}{coefficient \: \: of \: \: {x}^{2} } \\ \\ = > \frac{ - ( - k)}{5} = 0 \\ \\ = > k = 5 \\ \\ hence \: \: the \: \: value \: \: of \: k \: \\ is \: \: 5$

Answer 2

Answer:

k =20

Step-by-step explanation:

Given equation 5x^2-kx+6 =0

let p and q are the roots then wehave

sum of the roots p+q= -b/a then p+q = -(-k)/5

but given p+q =4 the k/5 =4 ,so k = 5×4

k= 20 , Hence answer is k =20