if the sum of the zeroes of the quadratic polynomial f(t)= kt square+ 2t+3k is equal to their product ,find the value of k?
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here is your by Sujeet,
kt²+2t+3k
so,
sum of zeroes=-b/a=-2/k
product of zeroes=c/a=3k/k=3
then
a+b=ab
-2/k=3
k=-2/3
that's all,
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mark brainliest
kt²+2t+3k
so,
sum of zeroes=-b/a=-2/k
product of zeroes=c/a=3k/k=3
then
a+b=ab
-2/k=3
k=-2/3
that's all,
follow me
mark brainliest
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