If the sum of the zeroes of the quadratic polynomial f(x)=kt2 + 2t+3k is equal to their product find the value of k
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Let the zeroes of the given equation be α and β
according to the question
α+β=αβ
we know that sum of roots=α+β=-2/k (-coefficient of t/coefficient of t2)
and product of roots=αβ=3k/k (constant term/coefficient of t2)
so
-2/k=3k/k
k=-2/3
Hope my answer is correct :)
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