Question

if the sum of the zeroes of the quadratic polynomial f (x)= kx^2-3x+5 is 1 , write the value of k

Answer 1

let the zeroes be a and b
so, given
a+b=1--(1)
now,
kx²-3x+5
x=k, y=(-3), z=5
from (1),
a+b=1
-y/x=1
-(-3)/k=1
3/k=1
3=k

Answer 2

Answer

The value of k for the polynomial $\bold{k x^{2}-3 x+5}$ is equal to 3

Step-by-step explanation:

The sum of the zeroes means the sum of the values in roots.

As we know according to the formula that sum of roots/zeroes of a quadratic equation is  

$a x^{2}+b x+c=0$__________________________________________(1)

zero1+zero2 or root1+root2= -b/a

$k x^{2}-3 x+5$

According to eqn. 1

We can see that,

a = k; b = -3; c = 5

Therefore,  

zero1+zero2 or root1+root2= -b/a

zero1+zero2=-(-3/k)

And according to the question zero1+zero2=1

On substituting we get,

1=-(-3/k)  k = 3  

Hence, the value of k is equal to 3.