If the sum of the zeroes of the quadratic polynomial k2 + 2y - 3k is equal to twice their product, find the value of k
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1
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Answered by
0
Answer:
Let α and β be the roots of given quadratic equation
x k 6 2 x k2 1 2 − + ^ ^ h h + + = 0
Now sum of roots,. α β +
k
1
6 =−− + ^ h = k + 6
Product of roots, αβ k
1
2 2 1 = ^ h + = 2 2^ h k + 1
According to given condition,
α β + 2
1 = αβ
k + 6 k 2
1 = 6 @ 2 2^ h + 1
k + 6 = 2 1 k + & k = 5
Hence, the value of k is 5.
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