Question

.If the sum of the zeroes of the quadratic polynomial ky2 + 2y – 3k is equal to twice their product, find the value of k.​

Answer 1

Step-by-step explanation:

f(y)= ky2 + 2y + 3k

Sum of the zeroes = -b/a = -2/k

Product of the zeroes = c/a = -3k/k = - 3

Given that sum of the zeroes is equal to the product of the zeroes, therefore,

-2/k = -3

k= 2/3.

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