Question

If the sum of the zeroes of the quadratic polynomial ky2 + 2y -3k is equal to twice their product, find the value of k

Answer 1

Answer:

The given polynomial is:

p(x)=(k^{2}-14)x^{2}-2x-4=1(k

2

−14)x

2

−2x−4=1

Comparing with the general Quadratic equation ax^{2}+bx+c=0ax

2

+bx+c=0 , we get the sum of zeroes of the polynomial=-\frac{b}{a}−

a

b

Therefore, -\frac{b}{a}=1−

a

b

=1 (Given)

\frac{2}{k^{2}-14}=1

k

2

−14

2

=1

2=k^{2}-142=k

2

−14

k^{2}=16k

2

=16

k={\pm}4k=±4

Answer 2

Answer:

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