if the sum of the zeroes of the quadratic polynomial
p(x) = kx² - 3x + 5 is 1 , find the value of k
Answers
Answer :
k = 3
Note :
★ The possible values of the variable for which the polynomial becomes zero are called its zeros .
★ A quadratic polynomial can have atmost two zeros .
★ The general form of a quadratic polynomial is given as ; ax² + bx + c .
★ If α and ß are the zeros of the quadratic polynomial ax² + bx + c , then ;
• Sum of zeros , (α + ß) = -b/a
• Product of zeros , (αß) = c/a
★ If α and ß are the zeros of a quadratic polynomial , then that quadratic polynomial is given as : k•[ x² - (α + ß)x + αß ] , k ≠ 0.
Solution :
Here ,
The given quadratic polynomial is ;
kx² - 3x + 5 .
Now ,
Comparing the given quadratic polynomial with the general quadratic polynomial ax² + bx + c , we have ;
a = k
b = -3
c = 5
Also ,
It is given that , the sum of zeros of the given quadratic polynomial is 1 .
=> Sum of zeros = 1
=> -b/a = 1
=> -(-3)/k = 1
=> 3/k = 1
=> 3 = k
=> k = 3
Hence , k = 3 .
Step-by-step explanation:
Given:
Sum of zeros of polynomial is kx2 – 3x + 5 is 1. We know that,
Sum of zeros = -(coefficient of x)/(coefficient of x2)
= -(-3) / k = 3/k
From above results,
we get
3/k = 1 Or k = 3
hope it helps
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