If the sum of the zeroes of the quadratic polynomial x2 + 2x + 3k is
equal to the product of its zeroes, then k =?
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Answer:
k = -2/3
Step-by-step explanation:
let ax^2 +bx + c be quadratic equation
Sum of roots(zeroes) = -b/a = -2/1 = -2
prodcts of roots(zeroes) = c/a = 3k/1 = 3k
A/c to question,
sum of zeroes = product of zeroes
=> -2 = 3k
=> k = -2/3
Hope it helps
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