If the sum of the zeros of a quadratic polynomial f x equal to k t square + 23 + 3 k is equal to the product find the value of k
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Answer:
- 2/3
Step-by-step explanation:
Given If the sum of the zeros of a quadratic polynomial f (x) equal to kt^2 + 2t + 3 k is equal to the product find the value of k
Given f(t) = kt^2 + 2t + 3k
Let α and β be the roots of the quadratic polynomial then
α + β = - b / a = - 2 / k and
α β = c / a = 3 k / k = 3
Now it is given α + β = α β
- 2 / k = 3
k = - 2 / 3
So the value of k is equal to - 2 / 3.
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