if the sum of the zeros of a quadratic polynomial ky^2 +2y-3k is equal to twice their product findk k
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0
Answer:
ky^2 +2y -3k-0
Sum of zeroes = -b/a
= -2/k
Product of zeroes = c/a
= -3k/k
=-3
According to the question,
Sum of zeroes = 2xproduct of zeroes
-2/k = -6
-6k=-2
K=1/3
Answered by
2
Answer:
ky²+2y -3k
let S α and β
the sum of zeros =α+β =-b/a
product zeros =αβ= ab
given condition α+β =2Xαβ
-2/k. =-2X3k
-6 K. =-2
K =2/6
K = 1/3.
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