Math, asked by sanjith931, 14 days ago

if the sum of the zeros of a quadratic polynomial ky^2 +2y-3k is equal to twice their product findk k

Answers

Answered by MrMaknae
0

Answer:

ky^2 +2y -3k-0

Sum of zeroes = -b/a

= -2/k

Product of zeroes = c/a

= -3k/k

=-3

According to the question,

Sum of zeroes = 2xproduct of zeroes

-2/k = -6

-6k=-2

K=1/3

Answered by shraddha8764
2

Answer:

ky²+2y -3k

let S α and β

the sum of zeros =α+β =-b/a

product zeros =αβ= ab

given condition α+β =2Xαβ

-2/k. =-2X3k

-6 K. =-2

K =2/6

K = 1/3.

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