Question

if the sum of the zeros of p(x)= kx^2+4x-35 is -1 . then find k

Answer 1

The value of k is 4 ......

Given :

The sum of the given polynomial is ( - 1 )

$p(x) = k {x}^{2} + 4x - 35$

Solution :

$let \: \: the \: \: zeroes \: \: of \: \: the \: \: polynomial \\ \: p(x) \: be \: \: \alpha \: \: and \: \: \beta$

According to the question ,,,,

$\alpha + \beta = - 1 \: \: \: \: \: \: \: - - - (1) \\ \\ but \: \: we \: \: know \: \: that \\ \: \: \alpha + \beta = \frac{ - b}{a} \\ \\from \: eq(1) we \: get \: \\ \\ - 1= - \frac{b}{a} \\ \\ - 1 = - \frac{4}{k} \\ \\ - 1k = - 4 \: \: \: \: \: \: \: \: \: ( \: by \: \: cross \: \: multiplying) \\ \\ k = \frac{ - 4}{ - 1} \\ \\ k = 4$

Hope it's helpful ......

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