Question

if the sum of the zeros of quadratic polynomial ky2+2y-3k is equal to twice their product find the value of k

Answer 1

Refer to the attachment please.

Answer 2

Given:

Quadratic polynomial ky² + 2y - 3k = 0

To Find:

Value of k

Solution:

we know,

sum of zeros = -b/a = -2 / k

product of zeros = c/a = -3k / k = -3

A/Q

sum of zeros = 2 * (product of zeros)

-2/k = 2 * (-3)

-2/k = -6

6k = 2

k = 1 / 3

So, the value of k = 1 / 3.