Question

if the sum of the zeros of the polynomial 2xsquare _3kxsquare+4x_5 is 6 find the value k​

Answer 1

Answer :

k = 8/9

Explanation :

Given polynomial,

⇒ 2x² - 3kx² + 4x - 5

On comparing with ax² + bx + c we get,

• a = (2 - 3k)
• b = 4
• c = -5

Where, the sum of the zeros given is 6

Find the value of ‘k’

Let's the zeros be α, and β

Then,

⇒ α + β = -b/a

Substitute the given values,

⇒ 6 = -4/(2 - 3k)

⇒ 6(2 - 3k) = -4

⇒ 12 - 18k = -4

⇒ 12 + 4 = 18k

⇒ 16 = 18k

⇒ 16/18 = k

⇒ 8/9

∴ The value of ‘k’ is 8/9.

Answer 2

Step-by-step explanation:

p(x) = 2x²-3kx² + 4x - 5

$sum \: \alpha + \beta + \gamma = \frac{ - b}{a}$

$\alpha + \beta + \gamma = 6 \\ 6 = \frac{ - 4}{2 - 3k } \\ 6(2 - 3k) = - 4 \\ 12 + 4 = 18k \\ \frac{16}{18 } = k \\ \frac{8}{ 9 } = k$

pls check the question and choose the correct ans

k= 4

or k= 8/9