Question

if the sum of the zeros of the polynomial kx^2+(2k+3)x+4 is -5 find the value of k​

Answer 1

Answer:

ans -1

Step-by-step explanation:

sum is -5

sum =alpha +beta =-b/a

-2k+3/k=-5

minus cancel both sides

2k+3/k=5/1

gives

2k+3=5k

2k-5k=-3

-3k =-3

minus cancel both sides

3k=3

k=3/3

k=1