if the sum of the zeros of the polynomial kx2+2x+3k is equal to their product find k
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Answer:
kx^2+2x+3k
here,
-b/a=sum of zeroes= -2/k
c/a = product of zeroes=3k/k= 3
ATQ, SUM OF ZEROES=SUM OF PRODUCT...
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Answer:
Sum of roots = -2/k
Product of roots = 3k/k = 3
Step-by-step explanation:
As given, -2/k = 3
Or, 3k = -2
Or, k = -2/3.
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