Question

If the sum of the zeros of the polynomial x^2-mx+b is p times their difference .Show that m^2 (p^2-1)=4 p^2n​

Answer 1

Answer:

Step-by-step explanation:

alpha + beta = -B/ A

p(alpha - beta) = m

alpha - beta = m/p---------------eq1

alpha + beta = m ----------------eq2

Eq1 + eq2

2(alpha) = m + m/p

alpha = m(p+1)/2p

Eq1-eq2

2(beta) = m - m/p

beta = m(p-1)/2p

Alpha * beta = C/A

m(p+1)/2p * m(p-1)/2p = b

m^2(p^2-1)=b* 4p^2

hence proved