Question

if the sum of the zeros of the polynomial x square - K + 3 X + 5 k minus 3 is equal to one fourth of the product of the zeros find the values of k

Answer 1

x^2+3x+5k-3
In above quadratic equation
So here a=1
b=3
c=5k-3
Sum of the zeroes (roots ) =-b/a
Product of the zeros =c/a
Here
Sum of the zeros=1/4 of product of the zeroes
-b/a=1/4×c/a
-3/1=1/4×5k-3/1
-3=1/4×5k-3
-3×4=5k-3
-12=5k-3
-5k=-3+12
-5k=9
5k=-9
K=-9/5
So the answer is K =-9/5