Question

If the sum of the zeros of the quadratic polynomial 3x square minus kx + 6 is 3 then find the value of k

Answer 1

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Here is your answer
IF the zeros of the equation is 3

so put the value of x = 3
$3 {x}^{2} - kx + 6 = 0 \\ 3(3) {}^{2} - 3k + 6 = 0 \\ 27 + 6 = 3k \\ 3k = 33 \\ k = \frac{33}{3} \\ k = 11$

If Sum of zeros is 3

Hence
Sum of zeros = -b/a
= -(-k)/3
k/3 = 3
k = 3×3
k = 9

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