If the sum of the zeros of the quadratic polynomial kx^2+2x+3k is equal to the product of its zeros,then the value of k is?....plz answer with explanation..plz
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Given :-
▪ The sum of the zeroes of the quadratic polynomial, p(x) = kx² + 2x + 3k is equal to the product of its zeroes.
To Find :-
▪ Value of k.
Solution :-
For a quadratic polynomial ax² + bx + c , the sum and product of zeroes can be calculated as -b/a and c/a.
Here, It is given that the sum and product of zeroes are equal. Which means, -b/a = c/a
Comparing the given quadratic polynomial with the standard form of quadratic polynomial, p(x) = ax² + bx + c , we get
- a = k ; b = 2 ; c = 3k
So, We have
⇒ -(2)/k = 3k / k
⇒ -2 = 3k
⇒ k = -2/3
∴ The value of k is -2/3 when the sum and product of zeroes are equal.
Some Information :-
☞ A quadratic polynomial having zeroes ɑ and β is in the form x² - (ɑ + β)x + ɑβ
☞ Zeroes of a quadratic polynomial can be found using the quadratic formula or completing square method.
⇒ Quadratic equation = { -b ± √(b² - 4ac) } / {2a}