if the sum of the zeros of the quadratic polynomial kX square + 2 X + 3 K is equal to the product find the value of k
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Hey !!
KX² + 2X - 3K
Sum of zeroes = -b/a
sum of zeroes = -2/k
and
Product of zeroes = c/a
product of zeroes = 3k/k = 3
Given that :
Sum of zeroes = product of zeroes
-2/k = 3
k = -3/2
KX² + 2X - 3K
Sum of zeroes = -b/a
sum of zeroes = -2/k
and
Product of zeroes = c/a
product of zeroes = 3k/k = 3
Given that :
Sum of zeroes = product of zeroes
-2/k = 3
k = -3/2
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