Question

if the sum of the zeros of the quadratic polynomial kxsquare + 2x + 3k is equal to the product of its zeroes then k =? ​

Answer 1

Answer:

alpha +betha= 2/k

alpha*betha =3k/k

alpha+betha =alpha*betha

2/k=3k/k ( k get cancel )

k=2/3

Explanation:

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Answer 2

Answer:

If k=/0, the equation can be written as x^2+3x/k+4=0. The sum of the solutions is (x1)+(x2)=-(3/k) and their product: 4. Since they are equal: -(3/k)=4, i.e. k=-(3/4). Therefore the solutions are 2 and 2, their sum being 4 and their product 4.

Proof: x^2+3x/(-3/4)+4=x^2–4x+4=0 i.e.(x-2)^2=0

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Explanation:

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