If the sum of the zeros of the quadratic polynomial is 1,write the value of k.
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SOLUTION :
Let α and β are the zeroes of the quadratic polynomial
Given : the quadratic polynomial : kx² - 3x + 5 and α + β = 1
On comparing with ax² + bx + c,
a = k , b= - 3 , c= 5
Sum of the zeroes = −coefficient of x / coefficient of x²
α + β = -b/a
1 = -(-3)/k
1 = 3/k
k × 1 = 3
k = 3
Hence, the value of k is 3 .
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Answered by
1
Solution :
Compare f(x) = kx²-3x+5 with
ax² + bx + c = 0. we get
a = k , b = -3 , c = 5
Sum of the zeroes = 1 [ given ]
=> ( -b/a ) = 1
=> -(-3)/k = 1
=> 3/k = 1
=> 3 = k
Therefore ,
k = 3
••••
Compare f(x) = kx²-3x+5 with
ax² + bx + c = 0. we get
a = k , b = -3 , c = 5
Sum of the zeroes = 1 [ given ]
=> ( -b/a ) = 1
=> -(-3)/k = 1
=> 3/k = 1
=> 3 = k
Therefore ,
k = 3
••••
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