if the sum of the zeros of the quadratic polynomials f(t) =kt+2t+3k is equal to their product find the value of k
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divya12342:
thanks,
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sum of the zeros=-b/a
=-2/k
product of the zeros=c/a
=3k/k
=3
Also
3=-2/k
k=-2/3
but it is only possible when equation is kt²+2t+3k
=-2/k
product of the zeros=c/a
=3k/k
=3
Also
3=-2/k
k=-2/3
but it is only possible when equation is kt²+2t+3k
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