Question

If the sum of thirteen positive consecutive integers is 169, what is the tenth integer?​

Answer 1

Answer:

100

Step-by-step explanation:

say first integar is a

next 12 integar will be a+1,a+2,a+3,a+4,a+5,a+6,a+7,a+8, a+9,a+10,a+11,a+12

sum of all thirteen= 13a+78=169

a= 169-78=91

10th digit= a+9=100

Answer 2

Answer:

10th integer is 16.

Step-by-step explanation:

Let 'a' be the first positive integer,

therefore, next integers will be a+1, a+2, a+3 ..... a+13

13a + 78 = 169

13a = 91

a = 7

So 10th integer will be a+9 = 7 + 9 = 16

10th Integer will be 16.