if the sum of three consec6 numbers is 36 .find the numbers
Answers
Answered by
0
Let the consecutive numbers be
x
(x+1)
(x+2)
∴ x + (x+1) + (x+2) = 36
⇒ 3x = 36 - 3
⇒ 3x = 33
⇒ x = 11
Therefore, the numbers are :
x = 11
(x+1) = 12
(x+2) = 13
I hope it helps you ^_^
x
(x+1)
(x+2)
∴ x + (x+1) + (x+2) = 36
⇒ 3x = 36 - 3
⇒ 3x = 33
⇒ x = 11
Therefore, the numbers are :
x = 11
(x+1) = 12
(x+2) = 13
I hope it helps you ^_^
Answered by
0
let be the numbers = first no.x
sec.no.x+1
thir.no.x×2
A.T.Q
x+x+1+x+2 =36
3x+3=36
3x=36-3
3x=33
x=33÷3
x=11
1 no.=11
2no.=11+1=12
3no.=11+2=13
verification= 11+12+13=36
sec.no.x+1
thir.no.x×2
A.T.Q
x+x+1+x+2 =36
3x+3=36
3x=36-3
3x=33
x=33÷3
x=11
1 no.=11
2no.=11+1=12
3no.=11+2=13
verification= 11+12+13=36
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