Question

 If the sum of three consecutive even numbers is 234, which is smallest among them?​

Answer 1

Answer:

let one number be x

then second number be x + 2

then the third one is x + 4

so according to question

x + x + 2 + x + 4= 234

3x + 6 =  234

3x = 234 - 6

3x = 228

x =  228/3

x = 76

so first number is 76

then second is 76 + 2 = 78

then third is 76 + 4 = 80

so smallest number is 76

Step-by-step explanation:

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Answer 2

Answer:

$let \\ the \: consecutive \: even \: numbers \: are \\ x,x + 2,x + 4 \\ then \\ x + x + 2 + x + 4 = 234 \\ 3x + 6 = 234 \\ 3x = 234 - 6 \\ x = 228 \div 3 \\ x = 76 \\ so \: the \: numbers \: are \\ 76, 78 \: and 80$

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