Question

if the sum of three consecutive integers is 20 more than the middle integer, what is the smallest of the three?

Answer 1

Let the sum of three consecutive integers be x,x + 1 and x + 2.

According to the question,

x + x + 1 + x + 2 = 20 + ( x + 1 )

=> 3x + 3 = 21 + x

=> 3x - x = 21 - 3

=> 2x = 18

=> x = 9

• x = 9

• x + 1 = 9 + 1 = 10

• x + 2 = 9 + 2 = 11

Answer 2

Given ,

The sum of three consecutive integers is 20 more than the middle integer

Let ,

The three consecutive integers be x , x + 1 and x + 2

According to the question ,

$\sf \Rightarrow x + x + 1 + x + 2 = 20 + x + 1 \\ \\ </p><p>\sf \Rightarrow 2x + 2 = 20 \\ \\ \sf \Rightarrow2x = 18 \\ \\ \sf \Rightarrow x = \frac{18}{2} \\ \\\sf \Rightarrow x = 9</p><p>$

$\therefore \bold{ \underline{ \sf{The \: smallest \: number \: is \: 9 }}}$