if the sum of three consecutive integers is 303cm then the smallest integer is
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Answer:
let , three consecutive no. ==> x , (x+1) , x+2
so, sum of three consecutive numbers = 303
so, x + x+ 1 + x +2 = 303
==> 3x + 3 = 303
==> 3(x+1) = 303
==> x+1 = 303/3
==> x + 1 = 101
==> x = 100
smaller integer = 100
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★ Question :- If the sum of three consecutive integers is 303, then find the smallest integer.
★ Solution :-
Let the three consecutive integers be x, x + 1 and x + 2
Given, their sum is 303
According to the question,
x + x + 1 + x + 2 = 303
➾ 3x + 3 = 303
➾ 3x = 303 - 3
➾ 3x = 300
➾ x = 100
∴ The smallest number ➾ x
➾
∴ The second number ➾ x + 1
➾ 100 + 1
➾
∴ The largest number ➾ x + 2
➾ 100 + 2
➾
★ Solution :-
Let the three consecutive integers be x, x + 1 and x + 2
Given, their sum is 303
According to the question,
x + x + 1 + x + 2 = 303
➾ 3x + 3 = 303
➾ 3x = 303 - 3
➾ 3x = 300
➾ x = 100
∴ The smallest number ➾ x
➾
∴ The second number ➾ x + 1
➾ 100 + 1
➾
∴ The largest number ➾ x + 2
➾ 100 + 2
➾
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