If the sum of three consecutive integers is 69 find the possible value of largest integer
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Answered by
3
Step-by-step explanation:
Let three consecutive number be x,x+1 and x+2.
x+x+2+x+3=69
3x=66
x=22
so largest number x+3=22+3=25
Answered by
0
The first integer is x. The second is x+1, and the third is x+2. Added together they give 69.
x + x+1 + x+2 = 69
3x + 3 = 69 (now divide equation by 3)
x + 1 = 23
x = 22
The three integers are 22, 23. And 24
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