If the sum of three consecutive natural numbers is 36, the smallest number is
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let smallest no. be x
x + x +1 + x +2 =36
3x + 3 = 36
3x = 36 - 3
3x = 33
x = 33/3
x= 11
so the smallest no. is 11
x + x +1 + x +2 =36
3x + 3 = 36
3x = 36 - 3
3x = 33
x = 33/3
x= 11
so the smallest no. is 11
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