if the sum of three consecutive number in ap is 15 and there product is 45 then find the numbers
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1
please refer the image
thanks
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Answered by
1
(a−b)+a+(a+b)⟹3a=15
a=5
(a−b)⋅a⋅(a+b)=45
⟹(5−b)⋅5⋅(5+b)=45
⟹5(25−b2)=45
⟹25−b2=9
⟹−b2=−16
⟹b=±4
This suggests that the first three terms are 1,5,9 or 9,5,1
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