Question

If the sum of three consecutive numbers in A.P is 15 and their product is 45, then find the numbers.​

Answer 1

Answer:

a=5,b=4

Step-by-step explanation:

take a-b,a,a+b as 3terms

Answer 2

The correct answer is the numbers are 1, 5 and 9.

Given: Sum of three consecutive numbers in A.P = 15.

Their product = 45.

To Find: The numbers.

Solution:

Let the first number = a - d

Let the second number = a

Let the third number = a + d

Sum of number = a-d + a + a+d

sum = 3a = 15

a = 5

Now put the value of a in numbers.

a - d = 5-d

a= 5

a + d = 5+d

Product = (5-d)(5)(5+d)

5($25-d^{2}$) = 45

$25-d^{2}$ = 9

$d^{2} =16$

d = 4

First number = 5-d = 5-4 = 1

Second number = a = 5

Third number = 5+d = d+4 = 9

Hence, the numbers are 1, 5 and 9.

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