Question

If the sum of three consecutive numbers is 36. Find the numbers.

Answer 1

Step-by-step explanation:

let the numbers are x , (x+1) & (x+2)

x + (x+1) + (x+2) = 36

x + x + 1 + x + 2 = 36

3x + 3 = 36

3x = 36 - 3

3x = 33

x = 33/3

x = 11

the numbers are 11, (11+1) & (11+2)

= 11 , 12 & 13 (ans.)

Answer 2

Answer:

11,12,13

Step-by-step explanation:

Let the first no.be x

Therefore,2nd no. =x+1

3rd no.=x+2

ATQ,

x+x+1+x+2=36

3x+3=36

3x=36-3

3x=33

x=33/3

x=11

Therefore,1st no.=11

2nd no.=x+1=11+1=12

3rd no. =x+2=11+2=13

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