Question

If the sum of three consecutive odd number is 219 find the smallest number among them

Answer 1

Answer:

one no is 2n-1 and 2nd is 2n+1 and 3rd is 2n+3

given that 2n-1+2n+1+2n+3=219

the n is 6n=216

n=216/6=36

smallest no. is -:2×36-1=71