Question

if the sum of three consecutive positive integer is 45 which is the larger number of them​

Answer 1

Answer:

let the numbers (x),(x+1),(x+2)

Step-by-step explanation:

so,

(x)+(x+1)+(x+2)=45. {given)

3x+3=45

3x=45-3

3x=42

x=42/3

x=13

so the numbers are

x=13

x+1 =14

x+2 =15

hence , the biggest number is 15.

Answer 2

Answer:

14,15 and 16

Step-by-step explanation:

let three consecutive integer are be=x,x+1,x+2

sum=45

then,x+(x+1)+(x+2)=45

3x+3=45

3x=45-3

x=42\3

x=14

so,x=14

x+1=14+1=15

x+2=14+2=16

hope you got your answer

plz thank me and make in brainlest