Question

*If the sum of three consecutive positive integers is 45, which is the largest number of them?*

1️⃣ 14
2️⃣ 18
3️⃣ 16
4️⃣ 20​

Answer 1

Question :- If the sum of three consecutive positive integers is 45, which is the largest number of them?*

1) 14

2) 18

3) 16

4) 20

Solution :-

Let us assume that, three consecutive positive integers are ,

• first integer = x
• second integer = (x + 1)
• third integer = (x + 1) + 1 = (x + 2)

given that, sum of all three is 45 .

so,

→ x + (x + 1) + (x + 2) = 45

→ x + x + x + 1 + 2 = 45

→ 3x + 3 = 45

→ 3x = 45 - 3

→ 3x = 42

dividing both sides by 3, we get,

→ x = 14 .

therefore,

→ Largest integer = Third integer = (x + 2) = 14 + 2 = 16 (Option 3) (Ans.)

Hence, Largest positive integer is 16.

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Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

If the sum of three consecutive positive integers is 45, which is the largest number of them

1. 14

2. 18

3. 16

4. 20

EVALUATION

Let the three consecutive positive integers are P - 1 , P , P + 1

Here it is given that the sum of three consecutive positive integers is 45

So by the given condition

$\sf{(P - 1) + P + (P + 1) = 45}$

$\sf{ \implies \: 3P = 45}$

$\sf{ \implies \: P = 15}$

Hence the consecutive positive integers are 14 , 15 , 16

Hence the largest number of them = 16

FINAL ANSWER

Hence the largest number of them

3. 16

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