Question

*If the sum of three consecutive positive integers is 45, which is the largest number of them?*

1️⃣ 14
2️⃣ 18
3️⃣ 16
4️⃣ 20*If the sum of three consecutive positive integers is 45, which is the largest number of them?*

1️⃣ 14
2️⃣ 18
3️⃣ 16
4️⃣ 20​

Answer 1

Answer:

Let the numbers be x, x+1 and x+2

x+ x+1 + x+2 = 45

3x + 3 = 45

3x= 45 - 3 = 42

So x= 42/3 = 14

So the numbers were 14, 15, 16

Step-by-step explanation:

Option 3 is the right answer

Answer 2

Question :

• If the sum of three consecutive positive integers is 45, which is the largest number of them ?

Given that :

• The sum of three consecutive positive integers is 45 .

Need To Find :

• The largest integers .

Let's Assume :

• The first integer be x .

Then ,

• Second Integer is x + 1 .
• Third Integer is x + 2 .

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀According To Question :

⠀⠀⠀⠀⠀➢ x + x + 1 + x+ 2 = 45

⠀⠀⠀⠀⠀➢ x + x + x + 1 + 2 = 45

⠀⠀⠀⠀⠀➢ 3 x + 1 + 2 = 45

⠀⠀⠀⠀⠀➢ 3 x + 3 = 45

⠀⠀⠀⠀⠀➢ 3x = 45 - 3

⠀⠀⠀⠀⠀➢ 3x = 42

⠀⠀⠀⠀⠀➢ x = 42\3

⠀⠀⠀⠀⠀➢ x = 14

Therefore ,

• First Integer = x = 14 .
• Second Integer = x + 1 = 14 + 1 = 15 .
• Third Integer = x + 2 = 14 + 2 = 16 .

⠀⠀⠀⠀∴⠀Hence , The largest integer is 16 .

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

Verification :

• L.H.S = 45 .

and ,

• First Integer = 14 .
• Second Integer = 15
• Third Integer = 16

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀Now Finding R.H.S :

⠀⠀⠀⠀⠀➢ R.H.S = 14 + 15 + 16

⠀⠀⠀⠀⠀➢ R.H.S = 20 + 15

⠀⠀⠀⠀⠀➢ R.H.S = 45

Therefore,

• L.H.S = R.H.S

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀∴⠀Hence , Verified

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀