Question

if the sum of three consecutive positive integers is 48 then the smallest integer is​

Answer 1

Answer:

let,the numbers are x,x+1,x+2

x+x+1+x+2=48

3x+3=48

3x=45

x=15

the smallest integer is 15

Answer 2

Consider the numbers to be (x-1), x & (x+1).

According to the question their sum is 48

x-1 + x + x+1 =48

3x = 48

x = 16

now the numbers are 16-1,16 & 16+1.

Hence 15,16,17