Question

If the sum of three consecutive term of an AP is 51 and the product of two extremes is 273,Find the numbers

Answer 1

A+a+d+a+2d=3a+3d =51, a+d=17 so product of extremes is a(a+2d)=273 so a=17-d (17-d)(a+2d)=(17-d)(17+d)=289-d2=273=d2=16 so d=4 now a=17-4=13 so numbers are 17,21,25

Answer 2

this is answer for above question