if the sum of three consecutive terms of an a.p is 51 and the product of two extermes is 273 find the numbers
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Answered by
2
let x, x+1,x+2 be the three consecutive numbers.
x+ x+1+ x+2=51
=>3x= 48
=>x=16
x+1=17
x+2=18
The numbers are 16, 17 and 18.
x+ x+1+ x+2=51
=>3x= 48
=>x=16
x+1=17
x+2=18
The numbers are 16, 17 and 18.
saji2:
273 is not right information
why
sometimes, when someone upload a question, question cant be understand by readers
I mean 273 is wrong.
oh.. in that way....
in this q, product of two extreme is 273, i ask to the questionare which nos.?
kindly look at my solution..... neeche hi hai
extreme Mtlb first and last
16*18=?
no... actually you have taken consecutive no. wrong... consecutive no means the no having common difference same.... means only 16 17 18 are not consecutive but 16 18 20 or 16 20 24 are also consecutive
Answered by
0
let nos. be a-d, a, a+d
sum=3a=51
a=17
product a^2-d^2=51
d sq=17*17-51
calculate d and put it above...
u will get nos.
sum=3a=51
a=17
product a^2-d^2=51
d sq=17*17-51
calculate d and put it above...
u will get nos.
oh sorry product is 273...kindly replace
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