Question

If the sum of three consecutive terms of an arithmetic progression is 24 then what is the value of its first term?​

Answer 1

$\large{\mathtt{\red{\underbrace{\overbrace{\blue{\boxed{\boxed{\pink{Âñswér}}}}}}}}}$

Let the first term be: a-d

Second term : a

Third term: a+d

Thus sum of AP with common difference d is

3 a = 24

a= 8

Now

Product of first and last term

( a-d ) ( a+d ) = 55

a^2 - d^2 = 55

64 -55 = d^2

d^2 = 9

d = +3 or - 3

So the desired terms are 5 , 8 , 11

Answer 2

Answer:

Let the first term be: a-d

Second term : a

Third term: a+d

Thus sum of AP with common difference d is

3 a = 24

a= 8

Now

Product of first and last term

( a-d ) ( a+d ) = 55

a^2 - d^2 = 55

64 -55 = d^2

d^2 = 9

d = +3 or - 3

So the desired terms are 5 , 8 , 11