Question

if the sum of three consecutive +ve integers is 48 then the smallest integer is​

Answer 1

Answer:

The third odd integer will then be ( 2 k + 3 ) + ( 2 ) = 2 k + 5 \left( {2k + 3} \right) + \left( 2 \right) = 2k + 5 (2k+3)+(2)=2k+5. The sum of our three consecutive odd integers is 45, so our equation setup will be: Now that we have our equation, let's proceed and solve for k. At this point, we have the value for k.

Step-by-step explanation:

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