If the sum of three numbers in A.P., is 24 and their product is 440, find the numbers.
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Let the numbers be (x - d), x and (x + d)
Sum of the 3 numbers is 24
(x - d) + x + (x + d) = 24
x - d + x + x + d = 24
3x = 24
x = 8
Product of the three numbers is 440
8 (8 - d) (8 + d) = 440
8( 8² - d²) = 440
64 - d² = 55
d² = 9
d = 3
Find the numbers:
x = 8
x - d = 8 - 3 = 5
x + d = 8 + 3 = 11
Answer: The numbers are 5, 8 and 11
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