Question

If the sum of three numbers in an A.P. is 9 and their product is 24, then numbers are *​

Answer 1

Answer:

2,3,4

Step-by-step explanation:

Let the numbers be a-d,a,a+d

Given sum is 9

a-d+a+a+d=9

3a=9

a=9/3

a=3

Given product is 24

(a-d)a(a+d)=24

(a^2-d^2)a=24

(3^2-d^2)3=24

(9-d^2)3=24

9-d^2=24/3

9-d^2=8

d^2=9-8

d^2=1

d=+or - 1

if d=1

a-d=3-1=2

a=3

a+d=3+1=4

if d=-1

a-d=3-(-1)=3+1=4

a=3

a+d=3+(-1)=3-1=2

The numbers are 2 ,3 and 4