If the sum of three
numbers in an A.P. is 9 and
their product is 24, then
numbers are (a) 2, 4, 6 (b)
1,5, 3 (c) 2, 8, 4 (d) 2, 3, 4*
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Answer:
a+a-d+a+d=9
3a=9
a=3
a(a-d)(a+d)=24
a(a^2-d^2)=24
a^3 -d^2a=24
27-d^26=24
3=d^2*6
d=1/4
c 2,4,8
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