Math, asked by singhlakhwinder33686, 8 months ago

If the sum of three
numbers in an A.P. is 9 and
their product is 24, then
numbers are (a) 2, 4, 6 (b)
1,5, 3 (c) 2, 8, 4 (d) 2, 3, 4*​

Answers

Answered by ayush0381
1

Answer:

a+a-d+a+d=9

3a=9

a=3

a(a-d)(a+d)=24

a(a^2-d^2)=24

a^3 -d^2a=24

27-d^26=24

3=d^2*6

d=1/4

c 2,4,8

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