Question

-. If the sum of three numbers of a arithmetic
sequence is 15 and the sum of their
squares is 83, then the numbers are
​

Answer 1

Answer:

Let the numbers be a-d,a,a+d.

Then,

a-d+a+a+d=15

3a=15

a=15/3

a=5.....1

(a-d)^2 +a^2 +(a+d)^2 =83

a^2-2ad+d^2+a^2+a^2+2ad+d^2=83

3a^2+2d^2 = 83

putting the value of eqn 1

3(5)^2 + 2d^2=83

75+2d^2=83

2d^2=83-75=8

d^2=8/2=4

d=√4=2......

The numbers are a-d=5-2=3

a=5

a+d =5+2=7

Numbers: 3,5,7

Answer 2

Answer:

3+5+7=15

9+25+49= 83

Step-by-step explanation:

let a no be X

there three nos are X-2,X,X+2

as per question, X-2+X+X+2=15

3X=15

X= 15/3 =5

therefore x-2=3

X+2=7